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Problems from 02/04/10

PROBLEM # 1

108^1/2/(1+(108^1/2/8)) =~ 4.52 feet

PROBLEM #2

There is a 6 foot wide alley. Both walls of the alley are perpendicular to the ground. Two ladders, one 10 feet long, the other 12 feet, are propped up from opposite corners to the adjacent wall, forming an X shape. All four feet of each ladder are firmly touching either the corner or the wall. The two ladders are also touching each other at the intersection of the X shape. What is the distance from the point of intersection to the ground?

SOLUTION

108^1/2/(1+(108^1/2/8)) =~ 4.52 feet

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Congratulations to Sitaram Chandawarkar, Sophia Farooqui and Ranganath Nayak, who were winners of the last set of puzzles.