For The Mathematically Inclined

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Solution to Problems from 06/18/15

Problem #1

Which is the smallest number which, when divided by 2, 3, 4, 5 and 6 will give 1, 2, 3, 4 and 5 as remainders, respectively?

Solution:
59.

Problem #2

The product of three consecutive odd numbers is 357,627. What is the smallest of the three?

Solution:
69.

Congratulations to Swati Dave, Prem Kapoor and Saba Lateef, who were winners of the last set of puzzles.